Why is Bi(V) a stronger oxidant/oxidizing agent than Sb (V)?
Bi (V) represents the +5-oxidation state of Bismuth (Bi). It means Bi has lost 5 electrons from its valence shell. Bi, therefore, wants to gain the lost electrons and is called an oxidizing agent. The process of electron uptake is a reduction reaction.
Bi (V) is a stronger oxidizing agent than Sb (V) and, therefore, will pick up the electrons faster than Sb (V). Due to the electron uptake, it will then go from a +5-oxidation state to a +3-oxidation state. Bi is now less by only three electrons due to the two-electron gain.
